Base | Representation |
---|---|
bin | 11110110000000000111… |
… | …110010011101100010111 |
3 | 21111000101101011201012201 |
4 | 132300000332103230113 |
5 | 234110202400240343 |
6 | 4254432505025331 |
7 | 305445404463412 |
oct | 36600076235427 |
9 | 7430341151181 |
10 | 2113140243223 |
11 | 7451a563a129 |
12 | 2a165a485247 |
13 | 124364509759 |
14 | 743c2b44b79 |
15 | 39e7ab1c94d |
hex | 1ec00f93b17 |
2113140243223 has 2 divisors, whose sum is σ = 2113140243224. Its totient is φ = 2113140243222.
The previous prime is 2113140243163. The next prime is 2113140243259. The reversal of 2113140243223 is 3223420413112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113140243223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2113140243191 and 2113140243200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113140243283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056570121611 + 1056570121612.
It is an arithmetic number, because the mean of its divisors is an integer number (1056570121612).
Almost surely, 22113140243223 is an apocalyptic number.
2113140243223 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113140243223 is an equidigital number, since it uses as much as digits as its factorization.
2113140243223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 2113140243223 its reverse (3223420413112), we get a palindrome (5336560656335).
The spelling of 2113140243223 in words is "two trillion, one hundred thirteen billion, one hundred forty million, two hundred forty-three thousand, two hundred twenty-three".
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