Base | Representation |
---|---|
bin | 110000000011000110001100… |
… | …110001000001010100100111 |
3 | 1000201012220101202121122121221 |
4 | 300003012030301001110213 |
5 | 210144222402140404312 |
6 | 2025234344050121211 |
7 | 62340203665342423 |
oct | 6003061461012447 |
9 | 1021186352548557 |
10 | 211319047591207 |
11 | 613729a531a776 |
12 | 1b84b069580207 |
13 | 90bb3ba7a315a |
14 | 3a27c79d03b83 |
15 | 1966d60243207 |
hex | c0318cc41527 |
211319047591207 has 2 divisors, whose sum is σ = 211319047591208. Its totient is φ = 211319047591206.
The previous prime is 211319047591103. The next prime is 211319047591213. The reversal of 211319047591207 is 702195740913112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211319047591207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211319047591007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105659523795603 + 105659523795604.
It is an arithmetic number, because the mean of its divisors is an integer number (105659523795604).
Almost surely, 2211319047591207 is an apocalyptic number.
211319047591207 is a deficient number, since it is larger than the sum of its proper divisors (1).
211319047591207 is an equidigital number, since it uses as much as digits as its factorization.
211319047591207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 952560, while the sum is 52.
The spelling of 211319047591207 in words is "two hundred eleven trillion, three hundred nineteen billion, forty-seven million, five hundred ninety-one thousand, two hundred seven".
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