Base | Representation |
---|---|
bin | 11110110000000100101… |
… | …011100101011101100011 |
3 | 21111000112201012211211001 |
4 | 132300010223211131203 |
5 | 234110314311203011 |
6 | 4254443010132431 |
7 | 305450061255232 |
oct | 36600453453543 |
9 | 7430481184731 |
10 | 2113202444131 |
11 | 745227763639 |
12 | 2a1677281117 |
13 | 12437437741c |
14 | 743cb0d6b19 |
15 | 39e813077c1 |
hex | 1ec04ae5763 |
2113202444131 has 2 divisors, whose sum is σ = 2113202444132. Its totient is φ = 2113202444130.
The previous prime is 2113202444047. The next prime is 2113202444167. The reversal of 2113202444131 is 1314442023112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2113202444131 - 235 = 2078842705763 is a prime.
It is a super-3 number, since 3×21132024441313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 2113202444131.
It is not a weakly prime, because it can be changed into another prime (2113202444231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056601222065 + 1056601222066.
It is an arithmetic number, because the mean of its divisors is an integer number (1056601222066).
Almost surely, 22113202444131 is an apocalyptic number.
2113202444131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113202444131 is an equidigital number, since it uses as much as digits as its factorization.
2113202444131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 2113202444131 its reverse (1314442023112), we get a palindrome (3427644467243).
The spelling of 2113202444131 in words is "two trillion, one hundred thirteen billion, two hundred two million, four hundred forty-four thousand, one hundred thirty-one".
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