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2113202444131 is a prime number
BaseRepresentation
bin11110110000000100101…
…011100101011101100011
321111000112201012211211001
4132300010223211131203
5234110314311203011
64254443010132431
7305450061255232
oct36600453453543
97430481184731
102113202444131
11745227763639
122a1677281117
1312437437741c
14743cb0d6b19
1539e813077c1
hex1ec04ae5763

2113202444131 has 2 divisors, whose sum is σ = 2113202444132. Its totient is φ = 2113202444130.

The previous prime is 2113202444047. The next prime is 2113202444167. The reversal of 2113202444131 is 1314442023112.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2113202444131 - 235 = 2078842705763 is a prime.

It is a super-3 number, since 3×21132024441313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 2113202444131.

It is not a weakly prime, because it can be changed into another prime (2113202444231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056601222065 + 1056601222066.

It is an arithmetic number, because the mean of its divisors is an integer number (1056601222066).

Almost surely, 22113202444131 is an apocalyptic number.

2113202444131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113202444131 is an equidigital number, since it uses as much as digits as its factorization.

2113202444131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 2113202444131 its reverse (1314442023112), we get a palindrome (3427644467243).

The spelling of 2113202444131 in words is "two trillion, one hundred thirteen billion, two hundred two million, four hundred forty-four thousand, one hundred thirty-one".