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211321213234041 = 31014378715927781
BaseRepresentation
bin110000000011001000001101…
…110110010010101101111001
31000201020002222200122201002210
4300003020031312102231321
5210144241321041442131
62025235343011245333
762340311443115061
oct6003101566225571
91021202880581083
10211321213234041
1161373906813239
121b84b5728a9849
1390bb674365511
143a2800379a3a1
151966e3a425146
hexc0320dd92b79

211321213234041 has 16 divisors (see below), whose sum is σ = 284557853032128. Its totient is φ = 139482755016000.

The previous prime is 211321213234009. The next prime is 211321213234081. The reversal of 211321213234041 is 140432312123112.

It is not a de Polignac number, because 211321213234041 - 25 = 211321213234009 is a prime.

It is not an unprimeable number, because it can be changed into a prime (211321213234081) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5303571 + ... + 21231351.

It is an arithmetic number, because the mean of its divisors is an integer number (17784865814508).

Almost surely, 2211321213234041 is an apocalyptic number.

It is an amenable number.

211321213234041 is a deficient number, since it is larger than the sum of its proper divisors (73236639798087).

211321213234041 is a wasteful number, since it uses less digits than its factorization.

211321213234041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15971672.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 211321213234041 its reverse (140432312123112), we get a palindrome (351753525357153).

The spelling of 211321213234041 in words is "two hundred eleven trillion, three hundred twenty-one billion, two hundred thirteen million, two hundred thirty-four thousand, forty-one".

Divisors: 1 3 101 303 43787 131361 4422487 13267461 15927781 47783343 1608705881 4826117643 697429746647 2092289239941 70440404411347 211321213234041