Base | Representation |
---|---|
bin | 1001100111000001101010… |
… | …01110100011000001101011 |
3 | 2202211012201121202012012122 |
4 | 10303200311032203001223 |
5 | 10232212101304233001 |
6 | 112535544550101455 |
7 | 4310513635064552 |
oct | 463406516430153 |
9 | 82735647665178 |
10 | 21132132102251 |
11 | 68080a5727035 |
12 | 245367034a88b |
13 | ba39a00a1a61 |
14 | 530b2cdb4d99 |
15 | 269a66719b1b |
hex | 1338353a306b |
21132132102251 has 2 divisors, whose sum is σ = 21132132102252. Its totient is φ = 21132132102250.
The previous prime is 21132132102127. The next prime is 21132132102283. The reversal of 21132132102251 is 15220123123112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21132132102251 - 238 = 20857254195307 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21132132102251.
It is not a weakly prime, because it can be changed into another prime (21132132101251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10566066051125 + 10566066051126.
It is an arithmetic number, because the mean of its divisors is an integer number (10566066051126).
Almost surely, 221132132102251 is an apocalyptic number.
21132132102251 is a deficient number, since it is larger than the sum of its proper divisors (1).
21132132102251 is an equidigital number, since it uses as much as digits as its factorization.
21132132102251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 21132132102251 its reverse (15220123123112), we get a palindrome (36352255225363).
The spelling of 21132132102251 in words is "twenty-one trillion, one hundred thirty-two billion, one hundred thirty-two million, one hundred two thousand, two hundred fifty-one".
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