Base | Representation |
---|---|
bin | 10011101011100100… |
… | …101110101000111111 |
3 | 2000112201212002201011 |
4 | 103223210232220333 |
5 | 321234312040132 |
6 | 13412531100051 |
7 | 1345450152562 |
oct | 235344565077 |
9 | 60481762634 |
10 | 21132143167 |
11 | 8a645a8a33 |
12 | 4119141627 |
13 | 1cba100c35 |
14 | 10467d04d9 |
15 | 83a350b47 |
hex | 4eb92ea3f |
21132143167 has 2 divisors, whose sum is σ = 21132143168. Its totient is φ = 21132143166.
The previous prime is 21132143119. The next prime is 21132143171. The reversal of 21132143167 is 76134123112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21132143167 - 215 = 21132110399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21132149167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10566071583 + 10566071584.
It is an arithmetic number, because the mean of its divisors is an integer number (10566071584).
Almost surely, 221132143167 is an apocalyptic number.
21132143167 is a deficient number, since it is larger than the sum of its proper divisors (1).
21132143167 is an equidigital number, since it uses as much as digits as its factorization.
21132143167 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6048, while the sum is 31.
Adding to 21132143167 its reverse (76134123112), we get a palindrome (97266266279).
The spelling of 21132143167 in words is "twenty-one billion, one hundred thirty-two million, one hundred forty-three thousand, one hundred sixty-seven".
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