2113273253641 has 4 divisors (see below), whose sum is σ = 2305389003984. Its totient is φ = 1921157503300.

The previous prime is 2113273253629. The next prime is 2113273253687. The reversal of 2113273253641 is 1463523723112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2113273253641 - 2⁷ = 2113273253513 is a prime.

It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a junction number, because it is equal to n+sod(n) for n = 2113273253594 and 2113273253603.

It is not an unprimeable number, because it can be changed into a prime (2113273253941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96057875155 + ... + 96057875176.

It is an arithmetic number, because the mean of its divisors is an integer number (576347250996).

Almost surely, 2^{2113273253641} is an apocalyptic number.

It is an amenable number.

2113273253641 is a deficient number, since it is larger than the sum of its proper divisors (192115750343).

2113273253641 is a wasteful number, since it uses less digits than its factorization.

2113273253641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192115750342.

The product of its digits is 181440, while the sum is 40.

Adding to 2113273253641 its reverse (1463523723112), we get a palindrome (3576796976753).

The spelling of 2113273253641 in words is "two trillion, one hundred thirteen billion, two hundred seventy-three million, two hundred fifty-three thousand, six hundred forty-one".