Base | Representation |
---|---|
bin | 1100010011010001010… |
… | …0111110110101101111 |
3 | 202012111001011000201221 |
4 | 3010310110332311233 |
5 | 11430301304004012 |
6 | 241030111244211 |
7 | 21160662343663 |
oct | 3046424766557 |
9 | 665431130657 |
10 | 211331313007 |
11 | 816970203a1 |
12 | 34b5a519667 |
13 | 16c0ba89109 |
14 | a32ad968a3 |
15 | 576d15a507 |
hex | 313453ed6f |
211331313007 has 2 divisors, whose sum is σ = 211331313008. Its totient is φ = 211331313006.
The previous prime is 211331313001. The next prime is 211331313071. The reversal of 211331313007 is 700313133112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211331313007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211331313001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105665656503 + 105665656504.
It is an arithmetic number, because the mean of its divisors is an integer number (105665656504).
Almost surely, 2211331313007 is an apocalyptic number.
211331313007 is a deficient number, since it is larger than the sum of its proper divisors (1).
211331313007 is an equidigital number, since it uses as much as digits as its factorization.
211331313007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 211331313007 its reverse (700313133112), we get a palindrome (911644446119).
The spelling of 211331313007 in words is "two hundred eleven billion, three hundred thirty-one million, three hundred thirteen thousand, seven".
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