Base | Representation |
---|---|
bin | 11110110000001100010… |
… | …011110101000001100111 |
3 | 21111000212122001102010011 |
4 | 132300030103311001213 |
5 | 234111100042343101 |
6 | 4254503421311051 |
7 | 305453204205046 |
oct | 36601423650147 |
9 | 7430778042104 |
10 | 2113330434151 |
11 | 745292a32412 |
12 | 2a16b2105487 |
13 | 124394a3b071 |
14 | 744000d255d |
15 | 39e8c68a751 |
hex | 1ec0c4f5067 |
2113330434151 has 2 divisors, whose sum is σ = 2113330434152. Its totient is φ = 2113330434150.
The previous prime is 2113330434109. The next prime is 2113330434161. The reversal of 2113330434151 is 1514340333112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2113330434151 - 215 = 2113330401383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113330434161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056665217075 + 1056665217076.
It is an arithmetic number, because the mean of its divisors is an integer number (1056665217076).
Almost surely, 22113330434151 is an apocalyptic number.
2113330434151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113330434151 is an equidigital number, since it uses as much as digits as its factorization.
2113330434151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 2113330434151 its reverse (1514340333112), we get a palindrome (3627670767263).
The spelling of 2113330434151 in words is "two trillion, one hundred thirteen billion, three hundred thirty million, four hundred thirty-four thousand, one hundred fifty-one".
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