Base | Representation |
---|---|
bin | 10011101011101001… |
… | …001011100111100001 |
3 | 2000112211001101220020 |
4 | 103223221023213201 |
5 | 321240111413213 |
6 | 13413012104053 |
7 | 1345463113644 |
oct | 235351134741 |
9 | 60484041806 |
10 | 21133310433 |
11 | 8a65225a14 |
12 | 4119605029 |
13 | 1cba41c321 |
14 | 1046a15a5b |
15 | 83a4d1923 |
hex | 4eba4b9e1 |
21133310433 has 4 divisors (see below), whose sum is σ = 28177747248. Its totient is φ = 14088873620.
The previous prime is 21133310383. The next prime is 21133310459. The reversal of 21133310433 is 33401333112.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21133310433 - 213 = 21133302241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (21133310333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3522218403 + ... + 3522218408.
It is an arithmetic number, because the mean of its divisors is an integer number (7044436812).
Almost surely, 221133310433 is an apocalyptic number.
It is an amenable number.
21133310433 is a deficient number, since it is larger than the sum of its proper divisors (7044436815).
21133310433 is an equidigital number, since it uses as much as digits as its factorization.
21133310433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7044436814.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 21133310433 its reverse (33401333112), we get a palindrome (54534643545).
The spelling of 21133310433 in words is "twenty-one billion, one hundred thirty-three million, three hundred ten thousand, four hundred thirty-three".
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