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2113333403143 = 6949304120507
BaseRepresentation
bin11110110000001100011…
…111001001111000000111
321111000212211122020210211
4132300030133021320013
5234111101322400033
64254504005100251
7305453241352024
oct36601437117007
97430784566724
102113333403143
11745294680026
122a16b30b7687
1312439553a571
147440066654b
1539e8ca752cd
hex1ec0c7c9e07

2113333403143 has 4 divisors (see below), whose sum is σ = 2113637530600. Its totient is φ = 2113029275688.

The previous prime is 2113333403123. The next prime is 2113333403177. The reversal of 2113333403143 is 3413043333112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2113333403143 - 221 = 2113331305991 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113333403113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152053305 + ... + 152067202.

It is an arithmetic number, because the mean of its divisors is an integer number (528409382650).

Almost surely, 22113333403143 is an apocalyptic number.

2113333403143 is a deficient number, since it is larger than the sum of its proper divisors (304127457).

2113333403143 is an equidigital number, since it uses as much as digits as its factorization.

2113333403143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 304127456.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 2113333403143 its reverse (3413043333112), we get a palindrome (5526376736255).

The spelling of 2113333403143 in words is "two trillion, one hundred thirteen billion, three hundred thirty-three million, four hundred three thousand, one hundred forty-three".

Divisors: 1 6949 304120507 2113333403143