211340143555555 has 12 divisors (see below), whose sum is σ = 295013588147280. Its totient is φ = 144918955580784.

The previous prime is 211340143555547. The next prime is 211340143555579. The reversal of 211340143555555 is 555555341043112.

It is not a de Polignac number, because 211340143555555 - 2³ = 211340143555547 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (49).

It is a junction number, because it is equal to n+sod(n) for n = 211340143555499 and 211340143555508.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 431306415175 + ... + 431306415664.

It is an arithmetic number, because the mean of its divisors is an integer number (24584465678940).

Almost surely, 2^{211340143555555} is an apocalyptic number.

211340143555555 is a deficient number, since it is larger than the sum of its proper divisors (83673444591725).

211340143555555 is an equidigital number, since it uses as much as digits as its factorization.

211340143555555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 862612830858 (or 862612830851 counting only the distinct ones).

The product of its (nonzero) digits is 4500000, while the sum is 49.

Adding to 211340143555555 its reverse (555555341043112), we get a palindrome (766895484598667).

The spelling of 211340143555555 in words is "two hundred eleven trillion, three hundred forty billion, one hundred forty-three million, five hundred fifty-five thousand, five hundred fifty-five".