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21134040000 = 26354296073
BaseRepresentation
bin10011101011101011…
…111101101111000000
32000112212102110200020
4103223223331233000
5321240303240000
613413035453440
71345502242653
oct235353755700
960485373606
1021134040000
118a65684067
1241198b7280
131cba616418
141046b6589a
1583a5c7ba0
hex4ebafdbc0

21134040000 has 280 divisors, whose sum is σ = 72295420560. Its totient is φ = 5440512000.

The previous prime is 21134039999. The next prime is 21134040007. The reversal of 21134040000 is 4043112.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21134040007) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 3476964 + ... + 3483036.

Almost surely, 221134040000 is an apocalyptic number.

21134040000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21134040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (36147710280).

21134040000 is an abundant number, since it is smaller than the sum of its proper divisors (51161380560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21134040000 is an equidigital number, since it uses as much as digits as its factorization.

21134040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6137 (or 6112 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 21134040000 its reverse (4043112), we get a palindrome (21138083112).

The spelling of 21134040000 in words is "twenty-one billion, one hundred thirty-four million, forty thousand".