Base | Representation |
---|---|
bin | 11110110000010001101… |
… | …010010011111011101111 |
3 | 21111001002212222200220201 |
4 | 132300101222103323233 |
5 | 234111241033321444 |
6 | 4254520345454331 |
7 | 305455344262633 |
oct | 36602152237357 |
9 | 7431085880821 |
10 | 2113420213999 |
11 | 745329683336 |
12 | 2a17181a13a7 |
13 | 1243aa513a33 |
14 | 7440bdc2dc3 |
15 | 39e954c1dd4 |
hex | 1ec11a93eef |
2113420213999 has 2 divisors, whose sum is σ = 2113420214000. Its totient is φ = 2113420213998.
The previous prime is 2113420213963. The next prime is 2113420214021. The reversal of 2113420213999 is 9993120243112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2113420213999 - 215 = 2113420181231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113420213909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056710106999 + 1056710107000.
It is an arithmetic number, because the mean of its divisors is an integer number (1056710107000).
Almost surely, 22113420213999 is an apocalyptic number.
2113420213999 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113420213999 is an equidigital number, since it uses as much as digits as its factorization.
2113420213999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 46.
The spelling of 2113420213999 in words is "two trillion, one hundred thirteen billion, four hundred twenty million, two hundred thirteen thousand, nine hundred ninety-nine".
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