Base | Representation |
---|---|
bin | 11110110000010001101… |
… | …010010011111011110001 |
3 | 21111001002212222200220210 |
4 | 132300101222103323301 |
5 | 234111241033322001 |
6 | 4254520345454333 |
7 | 305455344262635 |
oct | 36602152237361 |
9 | 7431085880823 |
10 | 2113420214001 |
11 | 745329683338 |
12 | 2a17181a13a9 |
13 | 1243aa513a35 |
14 | 7440bdc2dc5 |
15 | 39e954c1dd6 |
hex | 1ec11a93ef1 |
2113420214001 has 4 divisors (see below), whose sum is σ = 2817893618672. Its totient is φ = 1408946809332.
The previous prime is 2113420213999. The next prime is 2113420214021. The reversal of 2113420214001 is 1004120243112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 2113420214001 - 21 = 2113420213999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2113420214021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352236702331 + ... + 352236702336.
It is an arithmetic number, because the mean of its divisors is an integer number (704473404668).
Almost surely, 22113420214001 is an apocalyptic number.
It is an amenable number.
2113420214001 is a deficient number, since it is larger than the sum of its proper divisors (704473404671).
2113420214001 is an equidigital number, since it uses as much as digits as its factorization.
2113420214001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 704473404670.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 2113420214001 its reverse (1004120243112), we get a palindrome (3117540457113).
The spelling of 2113420214001 in words is "two trillion, one hundred thirteen billion, four hundred twenty million, two hundred fourteen thousand, one".
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