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2113425433 = 7301917919
BaseRepresentation
bin111110111111000…
…0101000000011001
312110021210010200001
41331332011000121
513312014103213
6545414013001
7103241551120
oct17576050031
95407703601
102113425433
11994a78899
124ab947161
13278b0b8c2
14160982ab7
15c581a1dd
hex7df85019

2113425433 has 4 divisors (see below), whose sum is σ = 2415343360. Its totient is φ = 1811507508.

The previous prime is 2113425343. The next prime is 2113425443. The reversal of 2113425433 is 3345243112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113425433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2113425443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150958953 + ... + 150958966.

It is an arithmetic number, because the mean of its divisors is an integer number (603835840).

Almost surely, 22113425433 is an apocalyptic number.

It is an amenable number.

2113425433 is a deficient number, since it is larger than the sum of its proper divisors (301917927).

2113425433 is an equidigital number, since it uses as much as digits as its factorization.

2113425433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 301917926.

The product of its digits is 8640, while the sum is 28.

The square root of 2113425433 is about 45972.0070586439. The cubic root of 2113425433 is about 1283.3023113582.

Adding to 2113425433 its reverse (3345243112), we get a palindrome (5458668545).

The spelling of 2113425433 in words is "two billion, one hundred thirteen million, four hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 7 301917919 2113425433