Base | Representation |
---|---|
bin | 1100010011010100001… |
… | …0010100111011101111 |
3 | 202012111212111221121022 |
4 | 3010311002110323233 |
5 | 11430312324344413 |
6 | 241031214124355 |
7 | 21161165362616 |
oct | 3046502247357 |
9 | 665455457538 |
10 | 211343199983 |
11 | 816a27aa243 |
12 | 34b624b06bb |
13 | 16c1138b826 |
14 | a32c7ac87d |
15 | 576e207608 |
hex | 3135094eef |
211343199983 has 2 divisors, whose sum is σ = 211343199984. Its totient is φ = 211343199982.
The previous prime is 211343199971. The next prime is 211343200027. The reversal of 211343199983 is 389991343112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211343199983 - 212 = 211343195887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211343190983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105671599991 + 105671599992.
It is an arithmetic number, because the mean of its divisors is an integer number (105671599992).
Almost surely, 2211343199983 is an apocalyptic number.
211343199983 is a deficient number, since it is larger than the sum of its proper divisors (1).
211343199983 is an equidigital number, since it uses as much as digits as its factorization.
211343199983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1259712, while the sum is 53.
The spelling of 211343199983 in words is "two hundred eleven billion, three hundred forty-three million, one hundred ninety-nine thousand, nine hundred eighty-three".
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