2113432001 has 4 divisors (see below), whose sum is σ = 2113549104. Its totient is φ = 2113314900.

The previous prime is 2113431967. The next prime is 2113432031. The reversal of 2113432001 is 1002343112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2113432001 is a prime.

It is a super-3 number, since 3×2113432001³ (a number of 29 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2113432031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25115 + ... + 69696.

It is an arithmetic number, because the mean of its divisors is an integer number (528387276).

Almost surely, 2^2113432001 is an apocalyptic number.

It is an amenable number.

2113432001 is a deficient number, since it is larger than the sum of its proper divisors (117103).

2113432001 is an equidigital number, since it uses as much as digits as its factorization.

2113432001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117102.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2113432001 is about 45972.0784933638. The cubic root of 2113432001 is about 1283.3036407515.

Adding to 2113432001 its reverse (1002343112), we get a palindrome (3115775113).

Subtracting from 2113432001 its reverse (1002343112), we obtain a square (1111088889 = 33333²).

It can be divided in two parts, 21134 and 32001, that added together give a palindrome (53135).

The spelling of 2113432001 in words is "two billion, one hundred thirteen million, four hundred thirty-two thousand, one".