Base | Representation |
---|---|
bin | 1100010011010100001… |
… | …0110111001100001101 |
3 | 202012111212210002002021 |
4 | 3010311002313030031 |
5 | 11430312343342201 |
6 | 241031221130141 |
7 | 21161166515662 |
oct | 3046502671415 |
9 | 665455702067 |
10 | 211343340301 |
11 | 816a2895705 |
12 | 34b62559951 |
13 | 16c1140a662 |
14 | a32c807a69 |
15 | 576e233ea1 |
hex | 31350b730d |
211343340301 has 2 divisors, whose sum is σ = 211343340302. Its totient is φ = 211343340300.
The previous prime is 211343340293. The next prime is 211343340343. The reversal of 211343340301 is 103043343112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 205055008900 + 6288331401 = 452830^2 + 79299^2 .
It is a cyclic number.
It is not a de Polignac number, because 211343340301 - 23 = 211343340293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211343340001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105671670150 + 105671670151.
It is an arithmetic number, because the mean of its divisors is an integer number (105671670151).
Almost surely, 2211343340301 is an apocalyptic number.
It is an amenable number.
211343340301 is a deficient number, since it is larger than the sum of its proper divisors (1).
211343340301 is an equidigital number, since it uses as much as digits as its factorization.
211343340301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 211343340301 its reverse (103043343112), we get a palindrome (314386683413).
The spelling of 211343340301 in words is "two hundred eleven billion, three hundred forty-three million, three hundred forty thousand, three hundred one".
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