211344013122 has 32 divisors (see below), whose sum is σ = 461545715520. Its totient is φ = 63983709120.

The previous prime is 211344013121. The next prime is 211344013129. The reversal of 211344013122 is 221310443112.

It is a junction number, because it is equal to n+sod(n) for n = 211344013092 and 211344013101.

It is not an unprimeable number, because it can be changed into a prime (211344013121) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1427193 + ... + 1568300.

It is an arithmetic number, because the mean of its divisors is an integer number (14423303610).

Almost surely, 2^211344013122 is an apocalyptic number.

211344013122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

211344013122 is an abundant number, since it is smaller than the sum of its proper divisors (250201702398).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211344013122 is a wasteful number, since it uses less digits than its factorization.

211344013122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2996578.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 211344013122 its reverse (221310443112), we get a palindrome (432654456234).

The spelling of 211344013122 in words is "two hundred eleven billion, three hundred forty-four million, thirteen thousand, one hundred twenty-two".