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211345251134309 is a prime number
BaseRepresentation
bin110000000011011110100110…
…100111100110101101100101
31000201022102000221012120012022
4300003132212213212231211
5210200140033242244214
62025254400143032525
762342122225650005
oct6003364647465545
91021272027176168
10211345251134309
1161383021562516
121b854160b9b745
1390c0a05471746
143a29244060005
151967895900d8e
hexc037a69e6b65

211345251134309 has 2 divisors, whose sum is σ = 211345251134310. Its totient is φ = 211345251134308.

The previous prime is 211345251134191. The next prime is 211345251134327. The reversal of 211345251134309 is 903431152543112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 200640935789284 + 10704315345025 = 14164778^2 + 3271745^2 .

It is a cyclic number.

It is not a de Polignac number, because 211345251134309 - 224 = 211345234357093 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211345251134309.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211345251154309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105672625567154 + 105672625567155.

It is an arithmetic number, because the mean of its divisors is an integer number (105672625567155).

Almost surely, 2211345251134309 is an apocalyptic number.

It is an amenable number.

211345251134309 is a deficient number, since it is larger than the sum of its proper divisors (1).

211345251134309 is an equidigital number, since it uses as much as digits as its factorization.

211345251134309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 44.

The spelling of 211345251134309 in words is "two hundred eleven trillion, three hundred forty-five billion, two hundred fifty-one million, one hundred thirty-four thousand, three hundred nine".