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2113623435045 = 351371028527219
BaseRepresentation
bin11110110000011101110…
…001100010011100100101
321111001122001101101210010
4132300131301202130211
5234112200044410140
64254552445320433
7305463362524053
oct36603561423445
97431561341703
102113623435045
11745423366311
122a1774266119
13124410658185
147442ada31d3
1539ea8265880
hex1ec1dc62725

2113623435045 has 16 divisors (see below), whose sum is σ = 3406482152640. Its totient is φ = 1119037613184.

The previous prime is 2113623435023. The next prime is 2113623435071. The reversal of 2113623435045 is 5405343263112.

It is not a de Polignac number, because 2113623435045 - 27 = 2113623434917 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2113623434994 and 2113623435012.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 514261555 + ... + 514265664.

It is an arithmetic number, because the mean of its divisors is an integer number (212905134540).

Almost surely, 22113623435045 is an apocalyptic number.

It is an amenable number.

2113623435045 is a deficient number, since it is larger than the sum of its proper divisors (1292858717595).

2113623435045 is a wasteful number, since it uses less digits than its factorization.

2113623435045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1028527364.

The product of its (nonzero) digits is 259200, while the sum is 39.

Adding to 2113623435045 its reverse (5405343263112), we get a palindrome (7518966698157).

The spelling of 2113623435045 in words is "two trillion, one hundred thirteen billion, six hundred twenty-three million, four hundred thirty-five thousand, forty-five".

Divisors: 1 3 5 15 137 411 685 2055 1028527219 3085581657 5142636095 15427908285 140908229003 422724687009 704541145015 2113623435045