Base | Representation |
---|---|
bin | 11110110000100001000… |
… | …011110010010010010111 |
3 | 21111001202220002112111221 |
4 | 132300201003302102113 |
5 | 234112303202101132 |
6 | 4255002134511211 |
7 | 305464632144412 |
oct | 36604103622227 |
9 | 7431686075457 |
10 | 2113678550167 |
11 | 7454514900a8 |
12 | 2a178a805507 |
13 | 12441bbb4882 |
14 | 7443442cb79 |
15 | 39ead000e97 |
hex | 1ec210f2497 |
2113678550167 has 2 divisors, whose sum is σ = 2113678550168. Its totient is φ = 2113678550166.
The previous prime is 2113678550029. The next prime is 2113678550183. The reversal of 2113678550167 is 7610558763112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2113678550167 - 235 = 2079318811799 is a prime.
It is a super-2 number, since 2×21136785501672 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113678550197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056839275083 + 1056839275084.
It is an arithmetic number, because the mean of its divisors is an integer number (1056839275084).
Almost surely, 22113678550167 is an apocalyptic number.
2113678550167 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113678550167 is an equidigital number, since it uses as much as digits as its factorization.
2113678550167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2116800, while the sum is 52.
The spelling of 2113678550167 in words is "two trillion, one hundred thirteen billion, six hundred seventy-eight million, five hundred fifty thousand, one hundred sixty-seven".
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