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21140003433 = 37046667811
BaseRepresentation
bin10011101100000010…
…101101101001101001
32000120021122102222010
4103230002231221221
5321243320102213
613413411350133
71345604031033
oct235402555151
960507572863
1021140003433
118a68a8751a
12411b8b2349
131cbb923893
141047878c53
1583ada4ac3
hex4ec0ada69

21140003433 has 4 divisors (see below), whose sum is σ = 28186671248. Its totient is φ = 14093335620.

The previous prime is 21140003431. The next prime is 21140003453. The reversal of 21140003433 is 33430004112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21140003433 - 21 = 21140003431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21140003431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3523333903 + ... + 3523333908.

It is an arithmetic number, because the mean of its divisors is an integer number (7046667812).

Almost surely, 221140003433 is an apocalyptic number.

It is an amenable number.

21140003433 is a deficient number, since it is larger than the sum of its proper divisors (7046667815).

21140003433 is an equidigital number, since it uses as much as digits as its factorization.

21140003433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7046667814.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 21140003433 its reverse (33430004112), we get a palindrome (54570007545).

The spelling of 21140003433 in words is "twenty-one billion, one hundred forty million, three thousand, four hundred thirty-three".

Divisors: 1 3 7046667811 21140003433