Base | Representation |
---|---|
bin | 11110110000110110000… |
… | …101001111011010100001 |
3 | 21111002200110202201001111 |
4 | 132300312011033122201 |
5 | 234114014000100103 |
6 | 4255101134303321 |
7 | 305506444110121 |
oct | 36606605173241 |
9 | 7432613681044 |
10 | 2114031253153 |
11 | 745612591076 |
12 | 2a1868957b41 |
13 | 124476ca6171 |
14 | 74469200c81 |
15 | 39ecde7086d |
hex | 1ec3614f6a1 |
2114031253153 has 8 divisors (see below), whose sum is σ = 2206433481408. Its totient is φ = 2021669677104.
The previous prime is 2114031253057. The next prime is 2114031253163. The reversal of 2114031253153 is 3513521304112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2114031253153 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2114031253163) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10056750 + ... + 10264807.
It is an arithmetic number, because the mean of its divisors is an integer number (275804185176).
Almost surely, 22114031253153 is an apocalyptic number.
2114031253153 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
2114031253153 is a deficient number, since it is larger than the sum of its proper divisors (92402228255).
2114031253153 is a wasteful number, since it uses less digits than its factorization.
2114031253153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20326103.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 2114031253153 its reverse (3513521304112), we get a palindrome (5627552557265).
The spelling of 2114031253153 in words is "two trillion, one hundred fourteen billion, thirty-one million, two hundred fifty-three thousand, one hundred fifty-three".
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