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2114031253153 = 23452320321557
BaseRepresentation
bin11110110000110110000…
…101001111011010100001
321111002200110202201001111
4132300312011033122201
5234114014000100103
64255101134303321
7305506444110121
oct36606605173241
97432613681044
102114031253153
11745612591076
122a1868957b41
13124476ca6171
1474469200c81
1539ecde7086d
hex1ec3614f6a1

2114031253153 has 8 divisors (see below), whose sum is σ = 2206433481408. Its totient is φ = 2021669677104.

The previous prime is 2114031253057. The next prime is 2114031253163. The reversal of 2114031253153 is 3513521304112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2114031253153 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2114031253163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10056750 + ... + 10264807.

It is an arithmetic number, because the mean of its divisors is an integer number (275804185176).

Almost surely, 22114031253153 is an apocalyptic number.

2114031253153 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

2114031253153 is a deficient number, since it is larger than the sum of its proper divisors (92402228255).

2114031253153 is a wasteful number, since it uses less digits than its factorization.

2114031253153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20326103.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 2114031253153 its reverse (3513521304112), we get a palindrome (5627552557265).

The spelling of 2114031253153 in words is "two trillion, one hundred fourteen billion, thirty-one million, two hundred fifty-three thousand, one hundred fifty-three".

Divisors: 1 23 4523 104029 20321557 467395811 91914402311 2114031253153