Base | Representation |
---|---|
bin | 11110110000111001101… |
… | …011001110000001010001 |
3 | 21111002211200012121211110 |
4 | 132300321223032001101 |
5 | 234114124413244221 |
6 | 4255111130403533 |
7 | 305511105412140 |
oct | 36607153160121 |
9 | 7432750177743 |
10 | 2114091540561 |
11 | 745643618980 |
12 | 2a1884b905a9 |
13 | 124486623ba0 |
14 | 74473215757 |
15 | 39ed43cd776 |
hex | 1ec39ace051 |
2114091540561 has 256 divisors, whose sum is σ = 4100795596800. Its totient is φ = 932616115200.
The previous prime is 2114091540557. The next prime is 2114091540577. The reversal of 2114091540561 is 1650451904112.
It is not a de Polignac number, because 2114091540561 - 22 = 2114091540557 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is not an unprimeable number, because it can be changed into a prime (2114091540361) by changing a digit.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 271416255 + ... + 271424043.
It is an arithmetic number, because the mean of its divisors is an integer number (16018732800).
Almost surely, 22114091540561 is an apocalyptic number.
2114091540561 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
2114091540561 is a deficient number, since it is larger than the sum of its proper divisors (1986704056239).
2114091540561 is a wasteful number, since it uses less digits than its factorization.
2114091540561 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7980.
The product of its (nonzero) digits is 43200, while the sum is 39.
The spelling of 2114091540561 in words is "two trillion, one hundred fourteen billion, ninety-one million, five hundred forty thousand, five hundred sixty-one".
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