Base | Representation |
---|---|
bin | 1100010011100100000… |
… | …1001001100100000011 |
3 | 202012200112012202011212 |
4 | 3010321001021210003 |
5 | 11430431430001011 |
6 | 241042002000335 |
7 | 21162636231341 |
oct | 3047101114403 |
9 | 665615182155 |
10 | 211410000131 |
11 | 81727485180 |
12 | 34b809460ab |
13 | 16c22179a45 |
14 | a3375da991 |
15 | 577500008b |
hex | 3139049903 |
211410000131 has 24 divisors (see below), whose sum is σ = 235249136976. Its totient is φ = 188415152640.
The previous prime is 211410000097. The next prime is 211410000143. The reversal of 211410000131 is 131000014112.
It is a de Polignac number, because none of the positive numbers 2k-211410000131 is a prime.
It is a super-2 number, since 2×2114100001312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211410000031) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 61579991 + ... + 61583423.
It is an arithmetic number, because the mean of its divisors is an integer number (9802047374).
Almost surely, 2211410000131 is an apocalyptic number.
211410000131 is a deficient number, since it is larger than the sum of its proper divisors (23839136845).
211410000131 is a wasteful number, since it uses less digits than its factorization.
211410000131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5543 (or 5490 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 211410000131 its reverse (131000014112), we get a palindrome (342410014243).
The spelling of 211410000131 in words is "two hundred eleven billion, four hundred ten million, one hundred thirty-one", and thus it is an aban number.
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