Base | Representation |
---|---|
bin | 11110110000111010010… |
… | …000011100111111101111 |
3 | 21111002212100120111221202 |
4 | 132300322100130333233 |
5 | 234114134413114411 |
6 | 4255112115520115 |
7 | 305511254363663 |
oct | 36607220347757 |
9 | 7432770514852 |
10 | 2114101301231 |
11 | 745649085247 |
12 | 2a18882b903b |
13 | 12448866082a |
14 | 744746368a3 |
15 | 39ed51aa83b |
hex | 1ec3a41cfef |
2114101301231 has 2 divisors, whose sum is σ = 2114101301232. Its totient is φ = 2114101301230.
The previous prime is 2114101301167. The next prime is 2114101301237. The reversal of 2114101301231 is 1321031014112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2114101301231 - 26 = 2114101301167 is a prime.
It is a super-2 number, since 2×21141013012312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2114101301237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057050650615 + 1057050650616.
It is an arithmetic number, because the mean of its divisors is an integer number (1057050650616).
Almost surely, 22114101301231 is an apocalyptic number.
2114101301231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114101301231 is an equidigital number, since it uses as much as digits as its factorization.
2114101301231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 2114101301231 its reverse (1321031014112), we get a palindrome (3435132315343).
The spelling of 2114101301231 in words is "two trillion, one hundred fourteen billion, one hundred one million, three hundred one thousand, two hundred thirty-one".
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