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2114101301231 is a prime number
BaseRepresentation
bin11110110000111010010…
…000011100111111101111
321111002212100120111221202
4132300322100130333233
5234114134413114411
64255112115520115
7305511254363663
oct36607220347757
97432770514852
102114101301231
11745649085247
122a18882b903b
1312448866082a
14744746368a3
1539ed51aa83b
hex1ec3a41cfef

2114101301231 has 2 divisors, whose sum is σ = 2114101301232. Its totient is φ = 2114101301230.

The previous prime is 2114101301167. The next prime is 2114101301237. The reversal of 2114101301231 is 1321031014112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2114101301231 - 26 = 2114101301167 is a prime.

It is a super-2 number, since 2×21141013012312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2114101301237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057050650615 + 1057050650616.

It is an arithmetic number, because the mean of its divisors is an integer number (1057050650616).

Almost surely, 22114101301231 is an apocalyptic number.

2114101301231 is a deficient number, since it is larger than the sum of its proper divisors (1).

2114101301231 is an equidigital number, since it uses as much as digits as its factorization.

2114101301231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 2114101301231 its reverse (1321031014112), we get a palindrome (3435132315343).

The spelling of 2114101301231 in words is "two trillion, one hundred fourteen billion, one hundred one million, three hundred one thousand, two hundred thirty-one".