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211411012121 is a prime number
BaseRepresentation
bin1100010011100100010…
…1000000101000011001
3202012200121010011100222
43010321011000220121
511430432204341441
6241042035405425
721162650644631
oct3047105005031
9665617104328
10211411012121
1181728006531
1234b81153875
1316c2244255a
14a3377c16c1
15577514ed4b
hex3139140a19

211411012121 has 2 divisors, whose sum is σ = 211411012122. Its totient is φ = 211411012120.

The previous prime is 211411012103. The next prime is 211411012133. The reversal of 211411012121 is 121210114112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124718454025 + 86692558096 = 353155^2 + 294436^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211411012121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211411012121.

It is not a weakly prime, because it can be changed into another prime (211411012321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105705506060 + 105705506061.

It is an arithmetic number, because the mean of its divisors is an integer number (105705506061).

Almost surely, 2211411012121 is an apocalyptic number.

It is an amenable number.

211411012121 is a deficient number, since it is larger than the sum of its proper divisors (1).

211411012121 is an equidigital number, since it uses as much as digits as its factorization.

211411012121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 211411012121 its reverse (121210114112), we get a palindrome (332621126233).

The spelling of 211411012121 in words is "two hundred eleven billion, four hundred eleven million, twelve thousand, one hundred twenty-one".