Base | Representation |
---|---|
bin | 1100010011100100010… |
… | …1001000000001011101 |
3 | 202012200121011200220022 |
4 | 3010321011020001131 |
5 | 11430432211324042 |
6 | 241042040201525 |
7 | 21162651132122 |
oct | 3047105100135 |
9 | 665617150808 |
10 | 211411042397 |
11 | 81728027255 |
12 | 34b811692a5 |
13 | 16c22453279 |
14 | a3377cc749 |
15 | 5775158cd2 |
hex | 313914805d |
211411042397 has 2 divisors, whose sum is σ = 211411042398. Its totient is φ = 211411042396.
The previous prime is 211411042313. The next prime is 211411042459. The reversal of 211411042397 is 793240114112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 204612380281 + 6798662116 = 452341^2 + 82454^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211411042397 is a prime.
It is a super-2 number, since 2×2114110423972 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211411042897) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105705521198 + 105705521199.
It is an arithmetic number, because the mean of its divisors is an integer number (105705521199).
Almost surely, 2211411042397 is an apocalyptic number.
It is an amenable number.
211411042397 is a deficient number, since it is larger than the sum of its proper divisors (1).
211411042397 is an equidigital number, since it uses as much as digits as its factorization.
211411042397 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 35.
The spelling of 211411042397 in words is "two hundred eleven billion, four hundred eleven million, forty-two thousand, three hundred ninety-seven".
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