Base | Representation |
---|---|
bin | 11110110000111011011… |
… | …100000001100111000001 |
3 | 21111002220201212000012222 |
4 | 132300323130001213001 |
5 | 234114210001041001 |
6 | 4255114104300425 |
7 | 305511614644223 |
oct | 36607334014701 |
9 | 7432821760188 |
10 | 2114121112001 |
11 | 745659286388 |
12 | 2a1892a71715 |
13 | 12448c7a8a92 |
14 | 74477112413 |
15 | 39ed6cc061b |
hex | 1ec3b7019c1 |
2114121112001 has 8 divisors (see below), whose sum is σ = 2165708428800. Its totient is φ = 2062534908960.
The previous prime is 2114121111997. The next prime is 2114121112063. The reversal of 2114121112001 is 1002111214112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2114121112001 - 22 = 2114121111997 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2114121112601) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4590320 + ... + 5029838.
It is an arithmetic number, because the mean of its divisors is an integer number (270713553600).
Almost surely, 22114121112001 is an apocalyptic number.
It is an amenable number.
2114121112001 is a deficient number, since it is larger than the sum of its proper divisors (51587316799).
2114121112001 is a wasteful number, since it uses less digits than its factorization.
2114121112001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 556879.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 2114121112001 its reverse (1002111214112), we get a palindrome (3116232326113).
It can be divided in two parts, 211412111 and 2001, that added together give a palindrome (211414112).
The spelling of 2114121112001 in words is "two trillion, one hundred fourteen billion, one hundred twenty-one million, one hundred twelve thousand, one".
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