Base | Representation |
---|---|
bin | 111111000000010… |
… | …1110111100001001 |
3 | 12110100002111110121 |
4 | 1332000232330021 |
5 | 13312203341411 |
6 | 545440543241 |
7 | 103250510323 |
oct | 17600567411 |
9 | 5410074417 |
10 | 2114121481 |
11 | 99540383a |
12 | 4b0021b21 |
13 | 278cc3674 |
14 | 160ac4613 |
15 | c5906571 |
hex | 7e02ef09 |
2114121481 has 2 divisors, whose sum is σ = 2114121482. Its totient is φ = 2114121480.
The previous prime is 2114121437. The next prime is 2114121487. The reversal of 2114121481 is 1841214112.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2099105856 + 15015625 = 45816^2 + 3875^2 .
It is a cyclic number.
It is not a de Polignac number, because 2114121481 - 223 = 2105732873 is a prime.
It is a super-2 number, since 2×21141214812 = 8939019272851266722, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2114121487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057060740 + 1057060741.
It is an arithmetic number, because the mean of its divisors is an integer number (1057060741).
Almost surely, 22114121481 is an apocalyptic number.
It is an amenable number.
2114121481 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114121481 is an equidigital number, since it uses as much as digits as its factorization.
2114121481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 512, while the sum is 25.
The square root of 2114121481 is about 45979.5767814363. The cubic root of 2114121481 is about 1283.4431793459.
Adding to 2114121481 its reverse (1841214112), we get a palindrome (3955335593).
The spelling of 2114121481 in words is "two billion, one hundred fourteen million, one hundred twenty-one thousand, four hundred eighty-one".
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