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2114124414007 is a prime number
BaseRepresentation
bin11110110000111011101…
…000100111110000110111
321111002220222001202201111
4132300323220213300313
5234114211322222012
64255114303135451
7305511655006114
oct36607350476067
97432828052644
102114124414007
11745660131211
122a1893ba4587
13124490393a28
147447773190b
1539ed7223ba7
hex1ec3ba27c37

2114124414007 has 2 divisors, whose sum is σ = 2114124414008. Its totient is φ = 2114124414006.

The previous prime is 2114124413957. The next prime is 2114124414013. The reversal of 2114124414007 is 7004144214112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2114124414007 - 27 = 2114124413879 is a prime.

It is a super-2 number, since 2×21141244140072 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2114124414007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2114124414047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057062207003 + 1057062207004.

It is an arithmetic number, because the mean of its divisors is an integer number (1057062207004).

Almost surely, 22114124414007 is an apocalyptic number.

2114124414007 is a deficient number, since it is larger than the sum of its proper divisors (1).

2114124414007 is an equidigital number, since it uses as much as digits as its factorization.

2114124414007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7168, while the sum is 31.

Adding to 2114124414007 its reverse (7004144214112), we get a palindrome (9118268628119).

The spelling of 2114124414007 in words is "two trillion, one hundred fourteen billion, one hundred twenty-four million, four hundred fourteen thousand, seven".