Base | Representation |
---|---|
bin | 11110110000111011101… |
… | …000100111110000110111 |
3 | 21111002220222001202201111 |
4 | 132300323220213300313 |
5 | 234114211322222012 |
6 | 4255114303135451 |
7 | 305511655006114 |
oct | 36607350476067 |
9 | 7432828052644 |
10 | 2114124414007 |
11 | 745660131211 |
12 | 2a1893ba4587 |
13 | 124490393a28 |
14 | 7447773190b |
15 | 39ed7223ba7 |
hex | 1ec3ba27c37 |
2114124414007 has 2 divisors, whose sum is σ = 2114124414008. Its totient is φ = 2114124414006.
The previous prime is 2114124413957. The next prime is 2114124414013. The reversal of 2114124414007 is 7004144214112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2114124414007 - 27 = 2114124413879 is a prime.
It is a super-2 number, since 2×21141244140072 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2114124414007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2114124414047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057062207003 + 1057062207004.
It is an arithmetic number, because the mean of its divisors is an integer number (1057062207004).
Almost surely, 22114124414007 is an apocalyptic number.
2114124414007 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114124414007 is an equidigital number, since it uses as much as digits as its factorization.
2114124414007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7168, while the sum is 31.
Adding to 2114124414007 its reverse (7004144214112), we get a palindrome (9118268628119).
The spelling of 2114124414007 in words is "two trillion, one hundred fourteen billion, one hundred twenty-four million, four hundred fourteen thousand, seven".
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