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2114131433 = 2717801223
BaseRepresentation
bin111111000000011…
…0001010111101001
312110100010000010012
41332000301113221
513312204201213
6545441101305
7103250551331
oct17600612751
95410100105
102114131433
11995410267
124b0027835
13278cc805b
14160ac80c1
15c59094a8
hex7e0315e9

2114131433 has 4 divisors (see below), whose sum is σ = 2121932928. Its totient is φ = 2106329940.

The previous prime is 2114131427. The next prime is 2114131447. The reversal of 2114131433 is 3341314112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2114131433 - 28 = 2114131177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2114131399 and 2114131408.

It is not an unprimeable number, because it can be changed into a prime (2114131133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3900341 + ... + 3900882.

It is an arithmetic number, because the mean of its divisors is an integer number (530483232).

Almost surely, 22114131433 is an apocalyptic number.

It is an amenable number.

2114131433 is a deficient number, since it is larger than the sum of its proper divisors (7801495).

2114131433 is an equidigital number, since it uses as much as digits as its factorization.

2114131433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7801494.

The product of its digits is 864, while the sum is 23.

The square root of 2114131433 is about 45979.6850032707. The cubic root of 2114131433 is about 1283.4451932331.

Adding to 2114131433 its reverse (3341314112), we get a palindrome (5455445545).

The spelling of 2114131433 in words is "two billion, one hundred fourteen million, one hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 271 7801223 2114131433