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2114151103 = 3757139219
BaseRepresentation
bin111111000000011…
…0110001010111111
312110100011000002201
41332000312022333
513312210313403
6545441332331
7103250662561
oct17600661277
95410130081
102114151103
11995424019
124b00370a7
13279003cac
14160ad1331
15c591021d
hex7e0362bf

2114151103 has 4 divisors (see below), whose sum is σ = 2171290360. Its totient is φ = 2057011848.

The previous prime is 2114151097. The next prime is 2114151119. The reversal of 2114151103 is 3011514112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2114151103 - 217 = 2114020031 is a prime.

It is a super-2 number, since 2×21141511032 = 8939269772632233218, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2114151203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28569573 + ... + 28569646.

It is an arithmetic number, because the mean of its divisors is an integer number (542822590).

Almost surely, 22114151103 is an apocalyptic number.

2114151103 is a deficient number, since it is larger than the sum of its proper divisors (57139257).

2114151103 is an equidigital number, since it uses as much as digits as its factorization.

2114151103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57139256.

The product of its (nonzero) digits is 120, while the sum is 19.

The square root of 2114151103 is about 45979.8989015852. The cubic root of 2114151103 is about 1283.4491736366.

Adding to 2114151103 its reverse (3011514112), we get a palindrome (5125665215).

The spelling of 2114151103 in words is "two billion, one hundred fourteen million, one hundred fifty-one thousand, one hundred three".

Divisors: 1 37 57139219 2114151103