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2114203300003 = 31311159605309
BaseRepresentation
bin11110110001000000010…
…101100011000010100011
321111010010110111120222001
4132301000111203002203
5234114342021100003
64255130202024431
7305513633352334
oct36610025430243
97433113446861
102114203300003
117456a0711453
122a18b64a8117
131244a3824032
1474483dc828b
1539ede10761d
hex1ec405630a3

2114203300003 has 8 divisors (see below), whose sum is σ = 2121151514400. Its totient is φ = 2107256319168.

The previous prime is 2114203299991. The next prime is 2114203300019. The reversal of 2114203300003 is 3000033024112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2114203300003 - 29 = 2114203299491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2114203300103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3190113 + ... + 3795421.

It is an arithmetic number, because the mean of its divisors is an integer number (265143939300).

Almost surely, 22114203300003 is an apocalyptic number.

2114203300003 is a deficient number, since it is larger than the sum of its proper divisors (6948214397).

2114203300003 is a wasteful number, since it uses less digits than its factorization.

2114203300003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 616781.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 2114203300003 its reverse (3000033024112), we get a palindrome (5114236324115).

The spelling of 2114203300003 in words is "two trillion, one hundred fourteen billion, two hundred three million, three hundred thousand, three".

Divisors: 1 313 11159 605309 3492767 189461717 6754643131 2114203300003