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211421011341 = 370473670447
BaseRepresentation
bin1100010011100110101…
…1001001110110001101
3202012201021221011201110
43010321223021312031
511430442234330331
6241043034002233
721163131642111
oct3047153116615
9665637834643
10211421011341
1181732716051
1234b84576379
1316c24533957
14a338c65741
155775e77946
hex3139ac9d8d

211421011341 has 4 divisors (see below), whose sum is σ = 281894681792. Its totient is φ = 140947340892.

The previous prime is 211421011273. The next prime is 211421011349. The reversal of 211421011341 is 143110124112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 211421011341 - 219 = 211420487053 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211421011349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35236835221 + ... + 35236835226.

It is an arithmetic number, because the mean of its divisors is an integer number (70473670448).

Almost surely, 2211421011341 is an apocalyptic number.

It is an amenable number.

211421011341 is a deficient number, since it is larger than the sum of its proper divisors (70473670451).

211421011341 is an equidigital number, since it uses as much as digits as its factorization.

211421011341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70473670450.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 211421011341 its reverse (143110124112), we get a palindrome (354531135453).

The spelling of 211421011341 in words is "two hundred eleven billion, four hundred twenty-one million, eleven thousand, three hundred forty-one".

Divisors: 1 3 70473670447 211421011341