Base | Representation |
---|---|
bin | 11110110001000000110… |
… | …000101011001010000111 |
3 | 21111010010221212212121121 |
4 | 132301000300223022013 |
5 | 234114400331124033 |
6 | 4255131014254411 |
7 | 305514050660455 |
oct | 36610060531207 |
9 | 7433127785547 |
10 | 2114210411143 |
11 | 7456a4729126 |
12 | 2a18b8957407 |
13 | 1244a51439cc |
14 | 74484d199d5 |
15 | 39edea5e62d |
hex | 1ec40c2b287 |
2114210411143 has 4 divisors (see below), whose sum is σ = 2115521144568. Its totient is φ = 2112899677720.
The previous prime is 2114210411141. The next prime is 2114210411153. The reversal of 2114210411143 is 3411140124112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2114210411143 - 21 = 2114210411141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2114210411141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655364293 + ... + 655367518.
It is an arithmetic number, because the mean of its divisors is an integer number (528880286142).
Almost surely, 22114210411143 is an apocalyptic number.
2114210411143 is a deficient number, since it is larger than the sum of its proper divisors (1310733425).
2114210411143 is a wasteful number, since it uses less digits than its factorization.
2114210411143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1310733424.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 2114210411143 its reverse (3411140124112), we get a palindrome (5525350535255).
The spelling of 2114210411143 in words is "two trillion, one hundred fourteen billion, two hundred ten million, four hundred eleven thousand, one hundred forty-three".
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