211421401333 has 2 divisors, whose sum is σ = 211421401334. Its totient is φ = 211421401332.

The previous prime is 211421401327. The next prime is 211421401423. The reversal of 211421401333 is 333104124112.

211421401333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 195343668529 + 16077732804 = 441977^2 + 126798^2 .

It is a cyclic number.

It is not a de Polignac number, because 211421401333 - 2⁹ = 211421400821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211421401298 and 211421401307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211421402333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105710700666 + 105710700667.

It is an arithmetic number, because the mean of its divisors is an integer number (105710700667).

Almost surely, 2^211421401333 is an apocalyptic number.

It is an amenable number.

211421401333 is a deficient number, since it is larger than the sum of its proper divisors (1).

211421401333 is an equidigital number, since it uses as much as digits as its factorization.

211421401333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 211421401333 its reverse (333104124112), we get a palindrome (544525525445).

The spelling of 211421401333 in words is "two hundred eleven billion, four hundred twenty-one million, four hundred one thousand, three hundred thirty-three".