Base | Representation |
---|---|
bin | 1001100111010100110110… |
… | …01101110001111111000111 |
3 | 2202212012022111220201002111 |
4 | 10303222123031301333013 |
5 | 10232344200334041012 |
6 | 112544411044321451 |
7 | 4311330126163144 |
oct | 463523315617707 |
9 | 82765274821074 |
10 | 21142433112007 |
11 | 6811501345139 |
12 | 24556660a3287 |
13 | ba49522517bc |
14 | 5314290d13cb |
15 | 269e6ac35ba7 |
hex | 133a9b371fc7 |
21142433112007 has 2 divisors, whose sum is σ = 21142433112008. Its totient is φ = 21142433112006.
The previous prime is 21142433111959. The next prime is 21142433112041. The reversal of 21142433112007 is 70021133424112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21142433112007 - 227 = 21142298894279 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21142433112007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21142433122007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10571216556003 + 10571216556004.
It is an arithmetic number, because the mean of its divisors is an integer number (10571216556004).
Almost surely, 221142433112007 is an apocalyptic number.
21142433112007 is a deficient number, since it is larger than the sum of its proper divisors (1).
21142433112007 is an equidigital number, since it uses as much as digits as its factorization.
21142433112007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 21142433112007 its reverse (70021133424112), we get a palindrome (91163566536119).
The spelling of 21142433112007 in words is "twenty-one trillion, one hundred forty-two billion, four hundred thirty-three million, one hundred twelve thousand, seven".
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