2114255131 has 2 divisors, whose sum is σ = 2114255132. Its totient is φ = 2114255130.

The previous prime is 2114255113. The next prime is 2114255137. The reversal of 2114255131 is 1315524112.

Together with previous prime (2114255113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2114255131 - 2²⁷ = 1980037403 is a prime.

It is a super-2 number, since 2×2114255131² = 8940149517919654322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2114255096 and 2114255105.

It is not a weakly prime, because it can be changed into another prime (2114255137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057127565 + 1057127566.

It is an arithmetic number, because the mean of its divisors is an integer number (1057127566).

Almost surely, 2^2114255131 is an apocalyptic number.

2114255131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2114255131 is an equidigital number, since it uses as much as digits as its factorization.

2114255131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1200, while the sum is 25.

The square root of 2114255131 is about 45981.0301211271. The cubic root of 2114255131 is about 1283.4702242387.

Adding to 2114255131 its reverse (1315524112), we get a palindrome (3429779243).

The spelling of 2114255131 in words is "two billion, one hundred fourteen million, two hundred fifty-five thousand, one hundred thirty-one".