Base | Representation |
---|---|
bin | 1001100111010101111011… |
… | …00111000001100000111011 |
3 | 2202212020210201201111122201 |
4 | 10303222331213001200323 |
5 | 10232401341044421210 |
6 | 112544544220331031 |
7 | 4311350334025012 |
oct | 463527547014073 |
9 | 82766721644581 |
10 | 21143010154555 |
11 | 6811778042803 |
12 | 24557a73a3a77 |
13 | ba4a1496cab3 |
14 | 5314819bda79 |
15 | 269ea171b53a |
hex | 133abd9c183b |
21143010154555 has 8 divisors (see below), whose sum is σ = 25377390306144. Its totient is φ = 16910556043200.
The previous prime is 21143010154529. The next prime is 21143010154571. The reversal of 21143010154555 is 55545101034112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-21143010154555 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 481485906 + ... + 481529815.
It is an arithmetic number, because the mean of its divisors is an integer number (3172173788268).
Almost surely, 221143010154555 is an apocalyptic number.
21143010154555 is a deficient number, since it is larger than the sum of its proper divisors (4234380151589).
21143010154555 is an equidigital number, since it uses as much as digits as its factorization.
21143010154555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 963020117.
The product of its (nonzero) digits is 60000, while the sum is 37.
Adding to 21143010154555 its reverse (55545101034112), we get a palindrome (76688111188667).
The spelling of 21143010154555 in words is "twenty-one trillion, one hundred forty-three billion, ten million, one hundred fifty-four thousand, five hundred fifty-five".
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