Base | Representation |
---|---|
bin | 111111000000101… |
… | …1010111000101001 |
3 | 12110100102122101021 |
4 | 1332001122320221 |
5 | 13312230121411 |
6 | 545444452441 |
7 | 103252160155 |
oct | 17601327051 |
9 | 5410378337 |
10 | 2114301481 |
11 | 995516aa6 |
12 | 4b00aa121 |
13 | 279057586 |
14 | 160b30065 |
15 | c593ea71 |
hex | 7e05ae29 |
2114301481 has 2 divisors, whose sum is σ = 2114301482. Its totient is φ = 2114301480.
The previous prime is 2114301479. The next prime is 2114301487. The reversal of 2114301481 is 1841034112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1414963456 + 699338025 = 37616^2 + 26445^2 .
It is a cyclic number.
It is not a de Polignac number, because 2114301481 - 21 = 2114301479 is a prime.
It is a super-2 number, since 2×21143014812 = 8940541505117586722, which contains 22 as substring.
Together with 2114301479, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2114301487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057150740 + 1057150741.
It is an arithmetic number, because the mean of its divisors is an integer number (1057150741).
Almost surely, 22114301481 is an apocalyptic number.
It is an amenable number.
2114301481 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114301481 is an equidigital number, since it uses as much as digits as its factorization.
2114301481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
The square root of 2114301481 is about 45981.5341305616. The cubic root of 2114301481 is about 1283.4796031777.
Adding to 2114301481 its reverse (1841034112), we get a palindrome (3955335593).
The spelling of 2114301481 in words is "two billion, one hundred fourteen million, three hundred one thousand, four hundred eighty-one".
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