2114310654451 has 4 divisors (see below), whose sum is σ = 2225590162600. Its totient is φ = 2003031146304.

The previous prime is 2114310654433. The next prime is 2114310654457. The reversal of 2114310654451 is 1544560134112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2114310654451 is a prime.

It is a super-2 number, since 2×2114310654451² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2114310654451.

It is not an unprimeable number, because it can be changed into a prime (2114310654457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55639754046 + ... + 55639754083.

It is an arithmetic number, because the mean of its divisors is an integer number (556397540650).

Almost surely, 2^{2114310654451} is an apocalyptic number.

2114310654451 is a deficient number, since it is larger than the sum of its proper divisors (111279508149).

2114310654451 is a wasteful number, since it uses less digits than its factorization.

2114310654451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111279508148.

The product of its (nonzero) digits is 57600, while the sum is 37.

Adding to 2114310654451 its reverse (1544560134112), we get a palindrome (3658870788563).

The spelling of 2114310654451 in words is "two trillion, one hundred fourteen billion, three hundred ten million, six hundred fifty-four thousand, four hundred fifty-one".