Base | Representation |
---|---|
bin | 1100010011101001001… |
… | …0111010001111011101 |
3 | 202012202000112122210112 |
4 | 3010322102322033131 |
5 | 11431002421330211 |
6 | 241044045215405 |
7 | 21163316346353 |
oct | 3047222721735 |
9 | 665660478715 |
10 | 211431433181 |
11 | 81738594141 |
12 | 34b87b61565 |
13 | 16c26742517 |
14 | a33a3b97d3 |
15 | 5776d3588b |
hex | 313a4ba3dd |
211431433181 has 2 divisors, whose sum is σ = 211431433182. Its totient is φ = 211431433180.
The previous prime is 211431433153. The next prime is 211431433229. The reversal of 211431433181 is 181334134112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 191923724281 + 19507708900 = 438091^2 + 139670^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211431433181 is a prime.
It is a super-2 number, since 2×2114314331812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211431433111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105715716590 + 105715716591.
It is an arithmetic number, because the mean of its divisors is an integer number (105715716591).
Almost surely, 2211431433181 is an apocalyptic number.
It is an amenable number.
211431433181 is a deficient number, since it is larger than the sum of its proper divisors (1).
211431433181 is an equidigital number, since it uses as much as digits as its factorization.
211431433181 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 32.
Adding to 211431433181 its reverse (181334134112), we get a palindrome (392765567293).
The spelling of 211431433181 in words is "two hundred eleven billion, four hundred thirty-one million, four hundred thirty-three thousand, one hundred eighty-one".
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