Base | Representation |
---|---|
bin | 11110110001000111111… |
… | …010011001100101110101 |
3 | 21111010110022122222221121 |
4 | 132301013322121211311 |
5 | 234120122040314031 |
6 | 4255150542143541 |
7 | 305520035610520 |
oct | 36610772314565 |
9 | 7433408588847 |
10 | 2114330401141 |
11 | 745756433412 |
12 | 2a1930b81bb1 |
13 | 1244c3c661ca |
14 | 74496c31bb7 |
15 | 39eea362011 |
hex | 1ec47e99975 |
2114330401141 has 4 divisors (see below), whose sum is σ = 2416377601312. Its totient is φ = 1812283200972.
The previous prime is 2114330401121. The next prime is 2114330401187. The reversal of 2114330401141 is 1411040334112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2114330401141 - 25 = 2114330401109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2114330401121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151023600075 + ... + 151023600088.
It is an arithmetic number, because the mean of its divisors is an integer number (604094400328).
Almost surely, 22114330401141 is an apocalyptic number.
It is an amenable number.
2114330401141 is a deficient number, since it is larger than the sum of its proper divisors (302047200171).
2114330401141 is an equidigital number, since it uses as much as digits as its factorization.
2114330401141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 302047200170.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 2114330401141 its reverse (1411040334112), we get a palindrome (3525370735253).
The spelling of 2114330401141 in words is "two trillion, one hundred fourteen billion, three hundred thirty million, four hundred one thousand, one hundred forty-one".
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