Base | Representation |
---|---|
bin | 1100010011101001101… |
… | …0010000111011111111 |
3 | 202012202011011121110211 |
4 | 3010322122100323333 |
5 | 11431003420024101 |
6 | 241044154413251 |
7 | 21163341626305 |
oct | 3047232207377 |
9 | 665664147424 |
10 | 211433361151 |
11 | 81739690701 |
12 | 34b88731227 |
13 | 16c26c68c2c |
14 | a33a75c275 |
15 | 57770b6c51 |
hex | 313a690eff |
211433361151 has 2 divisors, whose sum is σ = 211433361152. Its totient is φ = 211433361150.
The previous prime is 211433361121. The next prime is 211433361157. The reversal of 211433361151 is 151163334112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211433361151 - 29 = 211433360639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211433361157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105716680575 + 105716680576.
It is an arithmetic number, because the mean of its divisors is an integer number (105716680576).
Almost surely, 2211433361151 is an apocalyptic number.
211433361151 is a deficient number, since it is larger than the sum of its proper divisors (1).
211433361151 is an equidigital number, since it uses as much as digits as its factorization.
211433361151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480, while the sum is 31.
Adding to 211433361151 its reverse (151163334112), we get a palindrome (362596695263).
The spelling of 211433361151 in words is "two hundred eleven billion, four hundred thirty-three million, three hundred sixty-one thousand, one hundred fifty-one".
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