Base | Representation |
---|---|
bin | 111111000000111… |
… | …0011110001101001 |
3 | 12110100121211020021 |
4 | 1332001303301221 |
5 | 13312241402213 |
6 | 545451000441 |
7 | 103253063332 |
oct | 17601636151 |
9 | 5410554207 |
10 | 2114403433 |
11 | 99558665a |
12 | 4b0139121 |
13 | 279091abc |
14 | 160b59289 |
15 | c595ed8d |
hex | 7e073c69 |
2114403433 has 2 divisors, whose sum is σ = 2114403434. Its totient is φ = 2114403432.
The previous prime is 2114403419. The next prime is 2114403461. The reversal of 2114403433 is 3343044112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1898519184 + 215884249 = 43572^2 + 14693^2 .
It is a cyclic number.
It is not a de Polignac number, because 2114403433 - 29 = 2114402921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2114403398 and 2114403407.
It is not a weakly prime, because it can be changed into another prime (2114403493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057201716 + 1057201717.
It is an arithmetic number, because the mean of its divisors is an integer number (1057201717).
Almost surely, 22114403433 is an apocalyptic number.
It is an amenable number.
2114403433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114403433 is an equidigital number, since it uses as much as digits as its factorization.
2114403433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
The square root of 2114403433 is about 45982.6427361456. The cubic root of 2114403433 is about 1283.5002327191.
Adding to 2114403433 its reverse (3343044112), we get a palindrome (5457447545).
The spelling of 2114403433 in words is "two billion, one hundred fourteen million, four hundred three thousand, four hundred thirty-three".
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