Base | Representation |
---|---|
bin | 11110110001001111000… |
… | …110111101101110111101 |
3 | 21111010202201211221020121 |
4 | 132301033012331232331 |
5 | 234120343442313141 |
6 | 4255210534014541 |
7 | 305523033050512 |
oct | 36611706755675 |
9 | 7433681757217 |
10 | 2114451135421 |
11 | 7458085a6909 |
12 | 2a19654a7451 |
13 | 124512c89401 |
14 | 744a8c9d309 |
15 | 3a005c601d1 |
hex | 1ec4f1bdbbd |
2114451135421 has 2 divisors, whose sum is σ = 2114451135422. Its totient is φ = 2114451135420.
The previous prime is 2114451135409. The next prime is 2114451135427. The reversal of 2114451135421 is 1245311544112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1420353869796 + 694097265625 = 1191786^2 + 833125^2 .
It is a cyclic number.
It is not a de Polignac number, because 2114451135421 - 229 = 2113914264509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2114451135427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057225567710 + 1057225567711.
It is an arithmetic number, because the mean of its divisors is an integer number (1057225567711).
Almost surely, 22114451135421 is an apocalyptic number.
It is an amenable number.
2114451135421 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114451135421 is an equidigital number, since it uses as much as digits as its factorization.
2114451135421 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 19200, while the sum is 34.
Adding to 2114451135421 its reverse (1245311544112), we get a palindrome (3359762679533).
The spelling of 2114451135421 in words is "two trillion, one hundred fourteen billion, four hundred fifty-one million, one hundred thirty-five thousand, four hundred twenty-one".
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