Base | Representation |
---|---|
bin | 11110110001010010001… |
… | …110000010010001011011 |
3 | 21111010220101001012221111 |
4 | 132301102032002101123 |
5 | 234121000322230132 |
6 | 4255220040321151 |
7 | 305524235446213 |
oct | 36612216022133 |
9 | 7433811035844 |
10 | 2114503320667 |
11 | 745834aaa411 |
12 | 2a197aa731b7 |
13 | 124520a2b35a |
14 | 744b1ba5243 |
15 | 3a00a61c647 |
hex | 1ec5238245b |
2114503320667 has 2 divisors, whose sum is σ = 2114503320668. Its totient is φ = 2114503320666.
The previous prime is 2114503320623. The next prime is 2114503320673. The reversal of 2114503320667 is 7660233054112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2114503320667 - 211 = 2114503318619 is a prime.
It is a super-2 number, since 2×21145033206672 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2114503320367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057251660333 + 1057251660334.
It is an arithmetic number, because the mean of its divisors is an integer number (1057251660334).
Almost surely, 22114503320667 is an apocalyptic number.
2114503320667 is a deficient number, since it is larger than the sum of its proper divisors (1).
2114503320667 is an equidigital number, since it uses as much as digits as its factorization.
2114503320667 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 40.
Adding to 2114503320667 its reverse (7660233054112), we get a palindrome (9774736374779).
The spelling of 2114503320667 in words is "two trillion, one hundred fourteen billion, five hundred three million, three hundred twenty thousand, six hundred sixty-seven".
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